minta tolong kak.Terimakasih
Jawab:
Penjelasan dengan langkah-langkah:
Titik balik = (1, 1)
Titik potong sumbu Y = (0, 4)
Bentuk umum fungsi kuadrat : y = ax² + bx + c
(0,4) --> x = 0, y = 4
a (0²) + b (0) + c = 4
0 + 0 + c = 4
c = 4
(1, 1) --> x = 1, y = 1
-b/2a = 1
-b = 2a
b = -2a
-(b² - 4ac)/4a = 1
b² - 4ac = -4a
(-2a)² - 4a(4) = -4a
4a² - 16a = -4a
4a² - 16a + 4a = 0
4a² - 12a = 0
4a (a - 3) = 0
4a = 0
a = 0/4 = 0
a - 3 = 0
a = 3
b = -2(3) = -6
y = 3x² - 6x + 4
[answer.2.content]
